Ok
problem solved
thank you everybody
- Original Message -
From: "Richard Davey" <[EMAIL PROTECTED]>
To: "Dominique ANOKRE" <[EMAIL PROTECTED]>
Cc: "Php List" <[EMAIL PROTECTED]>
Sent: Friday, February 20, 2004 11:35 AM
Subject: Re[2]:
Dominique ANOKRE wrote:
I use a simple form like this :
print("\n");
print("\n");
This will result in
That is a hidden field without a value. This will get to the browser.
$_POST["hiddenField"] = $image_avant;
This will assign a value to $_POST["hiddenField"], which means just
that, nothing mo
Hello Dominique,
Friday, February 20, 2004, 11:29:21 AM, you wrote:
DA> I 've given a value se the code :
DA> $_POST["hiddenField"] = $image_avant;
DA> where $image_avant is a variable which contains a value !!
No, you've overwritten whatever might have been in the $_POST array
with the image_
ECTED]>; "Php List"
<[EMAIL PROTECTED]>
Sent: Friday, February 20, 2004 11:22 AM
Subject: RE: [PHP] display a hiddenfield
No value has been given to the hidden field.
e.g.
print ();
HTH.
Cheers,
Michael Egan
> -Original Message-
> From: Dominique ANOKRE [m
No value has been given to the hidden field.
e.g.
print ();
HTH.
Cheers,
Michael Egan
> -Original Message-
> From: Dominique ANOKRE [mailto:[EMAIL PROTECTED]
> Sent: 20 February 2004 11:17
> To: Php List
> Subject: [PHP] display a hiddenfield
>
>
> I use
I use a simple form like this :
print("\n");
print("\n");
$_POST["hiddenField"] = $image_avant;
print("\n");
print("\n");
and when i click on the submit button, i want to display the value of my hiddenField
(doing by the file image.php) :
but nothing is displaying !!
Please help !
6 matches
Mail list logo
