"rija" <[EMAIL PROTECTED]>
To: "php" <[EMAIL PROTECTED]>; "Ben C." <[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 1:34 PM
Subject: Re: [PHP] Using info from a MySQL Query
> Put your variables into {} like this '{$_POST['em
$sql = "query"
$result = mysql_query($sql)
while ($data = mysqlfetch_array($result)) {
echo $data['colum'];
}
- Original Message -
From: "Ben C." <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 3:09 AM
Subject: [P
mail";
rick
People will forget what you said. People will forget what you did.
But people will never forget how you made them feel.
- Original Message -
From: "Ben C." <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, November 05, 2002 7:09 PM
Subject: [PH
I think you might want something like this:
$sql ="SELECT company, name, email FROM $table_name
WHERE email = '$_POST[email]' AND password =
password('$_POST[password]');
$rs = mysql_query ($sql, mysql_connect ('server', 'user', 'pass');
$a = mysql_fetch_array ($rs);
echo $a['company
en C." <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, November 06, 2002 12:09 PM
Subject: [PHP] Using info from a MySQL Query
> I am using the following query:
>
> $sql ="SELECT company, name, email FROM $table_name
>WHERE email = '$_POST[ema
> I am using the following query:
>
> $sql ="SELECT company, name, email FROM $table_name
>WHERE email = '$_POST[email]' AND password =
> password('$_POST[password]')";
>
> Then I am echoing the $email on my form (it works because the person
has
> posted their e-mail name when logging in)
I am using the following query:
$sql ="SELECT company, name, email FROM $table_name
WHERE email = '$_POST[email]' AND password = password('$_POST[password]')";
Then I am echoing the $email on my form (it works because the person has posted their
e-mail name when logging in). How can I
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