* Thus wrote Scott Fletcher ([EMAIL PROTECTED]):
> Hi!
>
> I'm a little stuck with this simple math problem. I'm trying to get a
> number of days in integer, not float.
>
> --snip--
>$input_date = "12/16/2002";
>$UserInput = explode("/", $input_date);
>
>$UserInputMonth = $UserI
* Thus wrote Scott Fletcher ([EMAIL PROTECTED]):
> The int() function is for C/C++ programming only. This Int() function is
> not supported in PHP. In PHP it would be Intval(). For float, Floatval().
> For double, DoubleVal(). Etc. But beware of the Octual numbers.
You can cast like you can
> The int() function is for C/C++ programming only. This Int() function is
> not supported in PHP. In PHP it would be Intval(). For float,
Floatval().
> For double, DoubleVal(). Etc. But beware of the Octual numbers.
>
sorry, confusing my flash action script again :(
--
PHP General Maili
t; wrote in message
news:[EMAIL PROTECTED]
I used your snip you just posted and changed the $Days = round(Days) to
$Days = round($Days) and got 228.
-Original Message-
From: Scott Fletcher [mailto:[EMAIL PROTECTED]
Sent: Friday, August 01, 2003 9:18 AM
To: [EMAIL PROTECTED]
Subject: [PHP]
The int() function is for C/C++ programming only. This Int() function is
not supported in PHP. In PHP it would be Intval(). For float, Floatval().
For double, DoubleVal(). Etc. But beware of the Octual numbers.
"Skate" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
>
> >$Day
I used your snip you just posted and changed the $Days = round(Days) to
$Days = round($Days) and got 228.
-Original Message-
From: Scott Fletcher [mailto:[EMAIL PROTECTED]
Sent: Friday, August 01, 2003 9:18 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Simple Math Calculation Problem
Hi
>$Days = (($clockDate - $inputDate) / (24 * 3600));
$Days = int(($clockDate - $inputDate) / (24 * 3600));
you tried that?
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Hi!
I'm a little stuck with this simple math problem. I'm trying to get a
number of days in integer, not float.
--snip--
$input_date = "12/16/2002";
$UserInput = explode("/", $input_date);
$UserInputMonth = $UserInput[0];
$UserInputDay = $UserInput[1];
$UserInputYear = $UserI
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