On 10/3/09 9:53 AM, "Ralph Deffke" wrote:
> this is a clear sign that somebody is on a sin TRAIL, I would not even spend
> the time on what sin collections this guy got
i see it more as ignorance than sin.
to misunderstand the difference between $n++ and ++$n is a beginner error.
as k&r made
this is a clear sign that somebody is on a sin TRAIL, I would not even spend
the time on what sin collections this guy got
"Ashley Sheridan" wrote in message
news:1254577986.2385.8.ca...@localhost...
> On Sat, 2009-10-03 at 15:46 +0200, Ralph Deffke wrote:
>
> > yes for using
> > $num = $num++;
On Sat, 2009-10-03 at 15:46 +0200, Ralph Deffke wrote:
> yes for using
> $num = $num++;
> yes !!
>
> "Ashley Sheridan" wrote in message
> news:1254577641.2385.7.ca...@localhost...
> > On Sat, 2009-10-03 at 15:33 +0200, Ralph Deffke wrote:
> > > u increment after! asigning, so far so good, bu
yes for using
$num = $num++;
yes !!
"Ashley Sheridan" wrote in message
news:1254577641.2385.7.ca...@localhost...
> On Sat, 2009-10-03 at 15:33 +0200, Ralph Deffke wrote:
> > u increment after! asigning, so far so good, but for math reasons the
> > interpreter has to keep in mind the 123 you w
On Sat, 2009-10-03 at 15:33 +0200, Ralph Deffke wrote:
> u increment after! asigning, so far so good, but for math reasons the
> interpreter has to keep in mind the 123 you want to assign before increment
> to the same var.
>
> this is absolutely correct what php does here.
>
> $num = ++$num; wou
u increment after! asigning, so far so good, but for math reasons the
interpreter has to keep in mind the 123 you want to assign before increment
to the same var.
this is absolutely correct what php does here.
$num = ++$num; would print 124
the same like
$num++;
on the other hand this is just bu
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