Hehehe.. Yeah.
Thanks alot, this will do perfectly good.
- Richard
""Plutarck"" <[EMAIL PROTECTED]> wrote in message
9bqhpe$f3d$[EMAIL PROTECTED]">news:9bqhpe$f3d$[EMAIL PROTECTED]...
> If you want to make it easy on yourself, convert it into a timestamp (unix
> preferably). Then all you have
If you want to make it easy on yourself, convert it into a timestamp (unix
preferably). Then all you have to do is:
$dif = time() - $last_access_time;
if ($dif > 3600)
{
echo "The user has been inactive for more than an hour.";
}
That's if you want to make it easy on yourself. If you're a m
Greetings. (the thread was too far down to be read by anyone)
I am having some problems with the code itself! I have done like so,
that whenever peopel wishes to see the "onliners", I start a function called
DelOld(). This will not decrease server speed, nor create conflicts when
writing to t
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