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From: "Philip Olson" <[EMAIL PROTECTED]>
To: "Beauford.2002" <[EMAIL PROTECTED]>
Cc: "PHP General" <[EMAIL PROTECTED]>
Sent: Thursday, December 19, 2002 4:55 PM
Subject: Re: [PHP] Question about the exit() command
How about:
if (!$conn = mysql_
o: "PHP General" <[EMAIL PROTECTED]>
Sent: Thursday, December 19, 2002 3:45 PM
Subject: [PHP] Question about the exit() command
Hi,
Could someone clarify this for me. I want to be able to exit out of a PHP
webpage and return to the calling page if certain conditions are not met. It
MAIL PROTECTED]>
Cc: "PHP General" <[EMAIL PROTECTED]>
Sent: Thursday, December 19, 2002 4:55 PM
Subject: Re: [PHP] Question about the exit() command
>
> How about:
>
> if (!$conn = mysql_connect($host, $user, $pass)) {
> include 'static_html.inc&#x
On Thursday 19 December 2002 04:45 pm, Beauford.2002 wrote:
> I want to be able to exit out of a PHP webpage and
> return to the calling page if certain conditions are not met.
> It appears using exit() will do this, but I am unclear exactly how to use
> it.
exit won't do what you want. exit d
How about:
if (!$conn = mysql_connect($host, $user, $pass)) {
include 'static_html.inc';
exit;
}
print "Welcome, yes the database is connected";
exit ends the script, nothing after its use is executed.
Regards,
Philip Olson
On Thu, 19 Dec 2002, Beauford.2002 wrote:
> Hi,
Hi,
Could someone clarify this for me. I want to be able to exit out of a PHP
webpage and return to the calling page if certain conditions are not met. It
appears using exit() will do this, but I am unclear exactly how to use it.
any info is appreciated.
TIA
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