Hello,
I have a question (what a surprise :-) )
I browsed the archives, but didn't find what I'm looking for.
I have an object instance stored in some variable (like $myobject). I want
to save this instance into another variable (like $tempobject). I thought,
this will be the way:
$myobject
No worries...I just realized that my object never repopulated the underlying
classes with previous object references...Thanks guys, but I see my problem
now...
Cheers.
Adam Langley.
"Thies C. Arntzen" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> On Fri, M
OK, heres all the code...
I have a BoundForm class, a BoundFormPage class, and a BoundTextField...
I create a BoundForm, add a BoundFormPage object to it, then add a
BoundTextField to the BoundFormPagethen I add the root node (the
BoundForm) to the SESSION...
The Form, and Page survive seri
On Fri, May 03, 2002 at 12:34:01AM +1200, Adam Langley wrote:
> Hi everyone,
>
> Im trying to store an object which contains an associative array of classes,
> each of which contains an array of classes, so a 3-tier hierachy, in the
> session object. However, the final tier gets lost upon
> seria
Hi everyone,
Im trying to store an object which contains an associative array of classes,
each of which contains an array of classes, so a 3-tier hierachy, in the
session object. However, the final tier gets lost upon
serialization/deserialization, why is this and how can I prevent this from
happ
> Use & to reference one variable to another!
> $b =& $a;
Thanks.
Lucijan
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Hi,
Use & to reference one variable to another!
$b =& $a;
Lars
-Original Message-
From: Lucijan [mailto:[EMAIL PROTECTED]]
Sent: 21 March 2002 10:20
To: [EMAIL PROTECTED]
Subject: [PHP] Object reference
I can't understand why this works like it does.
class MyObj
I can't understand why this works like it does.
class MyObj {
var $Name;
function MyObj($Name) {
$this->Name = $Name;
}
}
$a = new MyObj('MyObjName');
$b = $a;
$b->Name = 'NoName';
echo $a->Name;
Last line will output 'MyObjName' instead of 'NoName' (like I was expecting)
I'd expect $a
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