Hi Ken,
> As we all know, this copies an object in PHP:
> $obj2 = $obj1
> Preferable a way to fix PHP not to copy the object, but the reference.
this will do want you want:
$obj2 = &$obj1;
--
Jimmy
Always keep a cool head and a warm heart
--
PHP General Mailing
As we all know, this copies an object in PHP:
$obj2 = $obj1
Assuming $obj1 is an object (of a class).
I want this never, ever to happen unless I want it to. All the time, I run
into something where PHP made a copy of my object for X odd reason -- I pass
an object to a function, I put
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