[PHP] imagecopy() no errors, but does nothing :-(

What I'm planning to do is to add the logo of the site over every image uploaded. Here is the code after upload: $dst_im = @ImageCreateFromJPEG ("../".$pathImg.$NomeFile); $src_im = @ImageCreateFromJPEG ("../imgsite/logo.jpg"); $dst_size = GetImageSize("../".$pathImg.$NomeFile);//800x60

[PHP] imagecopy or why men don't use maps.

Help! I have an image file which is a map of the local area. I want to put symbols on the map at various points, but I first need to get the php image function to work. My site has imaging enabled and I can create graphs from scratch, but this has stumped me so far. Any help will be greatly a

[PHP] ImageCopy() not working

I created a function (appears below) that crops a JPG and outputs it on the fly. However Apache crashes when I use the function. Unfortunately, Apache does not put an error message in the logs. I'm running it on a Windows2000 machine with Apache 1.3.20 and PHP 4.0.6 (installed via EasyPHP 1.5.0.0

RE: [PHP] imageCopy :-(

Hello! You should open "test.bmp" first. Best regards, Andrew Kirilenko. > -Original Message- > From: jtjohnston [mailto:[EMAIL PROTECTED]] > Sent: Saturday, November 10, 2001 1:15 PM > To: [EMAIL PROTECTED] > Subject: [PHP] imageCopy :-( > > >

[PHP] imageCopy :-(

Not that I'm sleep deprived ... :o) Simple, I create an image, add a bunch of text and what not. Now I want to add a graphic. (Probably a couple, who knows?) imageCopy("test.bmp",$image,10,10,10,10,350,500,50); <== doesn't work. Is this even the right function?? Description: int ImageCopyM

[PHP] ImageCopy

I am creating an image on the fly based on newest entries in one my mySQL tables. In this created image I am trying to add a small one to it. Now I am TRYING to use the below code: $image = ImageCreate(500, 70); $bg = ImageColorAllocate($image, 255, 255, 255); $blue = ImageColorAllocate($image,