> If (formfieldname = empty())
[snip]
$value = "0";
if(true==empty($value)) {
echo "it's empty";
}
[/snip]
May be good to know.
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if (empty($_REQUEST['formfieldname'])) {
//do something
} else {
//do something else
}
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On Monday 19 July 2004 07:34, Harlequin wrote:
> Simple as that eh...?
>
> If (formfieldname = empty())
The canonical form is:
if (empty($doo)) { ... }
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Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intrane
not enough =s.
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Simple as that eh...?
If (formfieldname = empty())
{
Do something
{
Else
{
do something else
}
??? am I on the right tracks...?
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-
Michael Mason
Arras People
www.arraspeople.co.uk
-
"John W. Holmes" <[EMAIL PROTECTED]> wrote i
Harlequin wrote:
Just wondering if there's a quick and easy way to validate form fields using
PHP.
Not really that concerned with actual content by using REGEX but want to
ensure users have at-least bothered to put something in and if not display
an error with the form field's name maybe.
empty()
-
Hello,
On 07/18/2004 07:42 PM, Harlequin wrote:
Just wondering if there's a quick and easy way to validate form fields using
PHP.
Not really that concerned with actual content by using REGEX but want to
ensure users have at-least bothered to put something in and if not display
an error with the for
Evening.
Just wondering if there's a quick and easy way to validate form fields using
PHP.
Not really that concerned with actual content by using REGEX but want to
ensure users have at-least bothered to put something in and if not display
an error with the form field's name maybe.
Any suggestion
Why don't you just put the quotes outside the php?
That will give you
foo
-jack
Mike wrote:
>
> What I need to do is append parenthesis to the front and back of
> ('1'.$row[0][0]), but when I do that it doesn't parse correctly. What I'm
> getting now is:
> Value=1San Francisco
> What I need is
What I need to do is append parenthesis to the front and back of
('1'.$row[0][0]), but when I do that it doesn't parse correctly. What I'm
getting now is:
Value=1San Francisco
What I need is:
Value="1San Francisco"
Thanks
Mike P
[EMAIL PROTECTED]
""Mike"" <[EMAIL PROTECTED]> wrote in message
9b
17 avril 2001 15:35
> À:Mike
> Cc: [EMAIL PROTECTED]
> Objet:Re: [PHP] Form Field
>
> Hi,
>
> How about enclose the parameters with quotes ???
>
> See ya,
>
> Marcelo Pereira
> Programmer
>
> - Original Message -
> From: Mike <
Hi,
How about enclose the parameters with quotes ???
See ya,
Marcelo Pereira
Programmer
- Original Message -
From: Mike <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, April 17, 2001 10:17 AM
Subject: [PHP] Form Field
> Im trying to pass a form variable t
Im trying to pass a form variable to anouther page with the following:
name="R1">
Everything works fine if there are no spaces(Buffalo) but if there are
spaces ( San Francisco) I only get the first word.I've never had this
problem before and I dont know what I did.Any suggestions?
Thanks
Mike P
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