Re: [PHP] Casting from parent class to child

On Fri, Oct 8, 2010 at 12:50 PM, Nathan Rixham wrote: > David Harkness wrote: >> >> Casting does not change an object. You must copy the relevant value(s) >> from >> the object returned into a new DateTimePlus. Since DateTime's constructor >> takes only a string, and I assume it won't accept your

Re: [PHP] Casting from parent class to child

David Harkness wrote: Casting does not change an object. You must copy the relevant value(s) from the object returned into a new DateTimePlus. Since DateTime's constructor takes only a string, and I assume it won't accept your format directly, unless you implement __toString I believe (not test

Re: [PHP] Casting from parent class to child

Casting does not change an object. You must copy the relevant value(s) from the object returned into a new DateTimePlus. Since DateTime's constructor takes only a string, and I assume it won't accept your format directly, you're better off converting the string into a Unix timestamp and creating a

[PHP] Casting from parent class to child

Hi, I'm trying to extends the base class DateTime. parent::createFromFormat("H.i d.m.Y", $string); returns a DateTime and I want to convert it into a DateTimePlus (my own extended class). What's the best way to do this plz ? Some code: class DateTimePlus extends DateTime { static functio