Dan,
Really, thanks for the help. Yeah, as you know I'm not experienced near
enough with PHP. Maybe you could provide me with an e-mail and prices for
consultation(I suppose this is what 'Analysis & Solutions' does?)
Regards,
Robert Packer
"Analysis & Solutions" <[EMAIL PROTECTED]> wrote
On Sat, Apr 06, 2002 at 12:32:33AM -0500, Analysis & Solutions wrote:
>
>
And following up to my own following up... As I shut down the computer,
I realized I made a boo boo. The single quotes shouldn't be there. So,
make that:
Later,
--Dan
--
PHP scripts that make y
On Fri, Apr 05, 2002 at 09:42:37PM -0500, Analysis & Solutions wrote:
> If you want to evaluate the variable $checkboxName, you need to write:
>
>$var = "checkbox$cb[$i]";
>if ($$var == 'validate')
>
> But, of course, that assumes you actually set the name of your
> checkbox to "che
Hey Rob:
On Fri, Apr 05, 2002 at 08:31:15PM -0800, Rob Packer wrote:
> if ("\$checkbox".$cb[$i]=="validate")
> {echo"can NOT get here";// HINT, HINT
Because you're making a string "$checkboxName" Of course it doesn't
equal "validate"
If you want to evaluate the variable $checkboxName, you
Sorry for the vague Subject, but I have this code that looks fine to me.
There's some logical error, because I can't get to the second if statement,
although when I echo "\$".$cb[$i] I get $checkboxName. If I hard code
$checkboxName it will work though. Anyone know why? TIA!
$num_fields= 8 ;//the
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