;
<[EMAIL PROTECTED]>
Sent: Wednesday, January 16, 2002 7:33 AM
Subject: [PHP] CONTINUE - variable problem - help!
> hi again!
>
> I tried it but it desn't give me any result back.
> It dosn't print any error message but it desn't print my result either.
>
whoops, typo:
echo (isset($row["somename_$var"]) && $row["somename_$var"] !== "") ?
$row["somename_$var"] : "Sorry, but \$row[\"somename_$var\"] is not set.";
above code should be correct :) (notice: it's only 1 line - email could
display it on multiple lines).
and here a smaller explanation of
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* On 16-01-02 at 13:43
* Dani said
> hi again!
>
> I tried it but it desn't give me any result back.
> It dosn't print any error message but it desn't print my result either.
>
> this is how I place the code:
>
>
> echo "...some html code..
> hi again!
>
> I tried it but it desn't give me any result back.
> It dosn't print any error message but it desn't print my result either.
>
> this is how I place the code:
>
>
> echo "...some html code...";
> $row["somename_$var"];
> echo "...the continuation of the html code";
>
> thanks!
I th
hi again!
I tried it but it desn't give me any result back.
It dosn't print any error message but it desn't print my result either.
this is how I place the code:
echo "...some html code...";
$row["somename_$var"];
echo "...the continuation of the html code";
thanks!
Stefan Rusterholz wrote:
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