numeric, you have to omit the '
thingys...
> -Original Message-
> From: Jeff Lewis [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, July 10, 2001 5:54 PM
> To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
> Subject: RE: [PHP] Average of column...
>
>
> This doesn't wor
rray etc.
Steve
> -Original Message-
> From: Jeff Lewis [mailto:[EMAIL PROTECTED]]
> Sent: 10 July 2001 16:54
> To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
> Subject: RE: [PHP] Average of column...
>
>
> This doesn't work:
>
> $age_result = mysql_query("
01 11:41 AM
> To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
> Subject: RE: [PHP] Average of column...
>
>
> if you do a
>
> $res = mysql_fetch_row($age_result)
>
> $res[0] will be the value of AVG(age).
>
>
> > -Original Message-
> > From: Jeff Lewis [mai
if you do a
$res = mysql_fetch_row($age_result)
$res[0] will be the value of AVG(age).
> -Original Message-
> From: Jeff Lewis [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, July 10, 2001 5:27 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Average of column...
>
>
&g
sday, July 10, 2001 11:27 AM
Subject: [PHP] Average of column...
> I am trying to obtain the average age for a few teams in my database.
> $age_result = mysql_query("select AVG(age) FROM bat_rost WHERE ownerID =
> '$teamID'");
> while(($row = mysql_fetch_object($age_res
I am trying to obtain the average age for a few teams in my database.
Am using the below code:
$age_result = mysql_query("select AVG(age) FROM bat_rost WHERE ownerID =
'$teamID'");
while(($row = mysql_fetch_object($age_result))){
$age=$row->age;
echo "Average age - ".$teamID.$age;}
How can I
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