Hi All
I am porting some perl to PHP and have struck a small snag. The perl
script has quite a few substitutions that take place so data can be fed
into a html page.
The script uses the following perl syntax
$html = `cat search_results.html`;
$html =~ s/%Accom/$accom/g;
As I understand perl tha
Hi Jake
I am getting nothing at all.
Regards
Richard
> What is the result your getting?
>
> Jake
>
>
>> -Original Message-
>> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
>> Sent: Saturday, March 24, 2007 11:57 PM
>> To: Jake McHenry
>> Cc: php-general@lists.php.net
>> Subject: RE
Hi Jake
I tried that and got the same result.
Regards
Richard
> What if you put $temp = $data->legs->leg[$k]['legId'];
> And then put that into $legrow[$temp];
>
> Do you have anything in $temp?
>
> Jake
>
>
>> -Original Message-
>> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
>> S
Hi Jake
Thanks for the answer.
That is what I had in my example that did not work.
I had tried that and then wondered how I might access that key.
I have tried $legrow["number"];
where number is a value I know to be one of the legId's. Is this correct?
Regards
Richard
> $legrow["$data->leg
Hi All
I am having a bit of trouble with PHP arrays and would appreciate some help.
I currently have the following piece of code
$count=count($data->legs->leg);
$k=0;
while($k < $count)
{
$legrow[$k]=$data->legs->leg[$k]['legId'].$VM.$data->
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