";
}
?>
Can someone PLEASE tell me why the coding above gives the following error:
Warning: Supplied argument is not a valid MySQL result resource in
/var/web/somesite.com/html/index.php on line 5
It's absurd. It's driving me nuts. I'm about to introduce my computer to the
pavement 40 feet
Hi,
Is there any function or command in PHP that will return the width an image
(GIF)?
Thanks.
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To un
other table which I want to affect the timestamps. Is
there a command for 'manually' updating a timestamp rather than by SQL's own
logic?
Thanks in advance.
Cosmin Laslau
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Ok, there's a table with 4 fields, I want to delete from it when two of the
variables passed (through the function below) match up with the table's
contents. However, I have only been able to get it to work with one 'where'
clause, not two.
Here's my code for one:
function delete_one_sub($sel
Hi,
Say I'm not really confident in the prowess of my server, and I want to
download my database onto my computer. Can that be done? What can I look
(FTP access) in the directory structure. I guess, where is it usually
located?
Thanks.
Cosmin L
I've got a website which will alllow users to upload photos (jpegs) and,
once approved, they'll be up for display. To do that, I need an
auto-thumbnail script, preferrably for on-the-fly thumb generation.
Any ideas? Also, what kind of libraries would I need.
Thanks. The site is http://www.flat
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