Hello,
The second part of Zend Framework is now on my blog, this time is about layouts
http://yuriyarlei.net/en/zend-framework-how-to-develop-layouts
Yuri Yarlei.
http://www.yuriyarlei.net.net (under construction)
Programmer PHP, JAVA, CSS, PostregreSQL;
Today PHP, tomorrow Java, after the
Hi people,
I wanna share the tutorial about Zend Framework there I'm doing
http://www.yuriyarlei.net/en/zend-framework-how-to-develop-introduction
Att,
Yuri Yarlei.
Java - OCJP 6
ZCE - Zend Certified Engineer for php 5.3
www.yuriyarlei.net/en
PHP, JAVA, CSS, ORACLE 10g, PostgreSQL;
Hi,
I like to share with the list, that I passed in the ZCE and now I'm a Zend
Certified Engineer.
I did a post when I started studying in my blog:
http://www.yuriyarlei.net/en/zend-php-certification
Att,
Yuri Yarlei.
OCJP 6, ZCE - Zend Certified Engineer for php 5.3
www.yuriyarlei.net/en
;FacebookRestClientException' with message 'Invalid parameter'
If i generate the token again, its work for the first time again.
Please someone have any recent tutorial to integrate facebook to some php
site?
Atenciosamente,
Yuri Yarlei.
www.yuriyarlei.net (under construction)
Programmer PHP, JAVA, CSS, ORACLE 10g, PostgreSQL;
Next step is the SCJP.
"Se você ainda não esta com dor de cabeça, é por que ainda cabe um pouco
mais de conhecimento."
PGSQL, PLSQL,
JAVA...
ATT,
Yuri Yarlei.
Programmer PHP, JAVA, CSS, ORACLE 10g, PostgreSQL;
Ash,
I think the apache is working, because he recieve the error "[27-Oct-2009
13:05:00] PHP Fatal error: Call to undefined function", if apache are not
started he will receive some error about apache starting or someting like that.
Yuri Yarlei.
http://www.yuriyarlei.net.
Hi all,
If the basic functions of php not work, maybe the extension for php5 or 4 are
disabled, or the library is missing, sometimes apache does not show the erros
for missing library, or yet, the library for php4 or 5 are both on, or they
crash
Yuri Yarlei.
www.yuriyarlei.net (under
Hi all,
If the basic functions of php not work, maybe the extension for php5 or 4 are
disabled, or the library is missing, sometimes apache does not show the erros
for missing library, or yet, the library for php4 or 5 are both on, or they
crash
Yuri Yarlei.
www.yuriyarlei.net (under
I agree, o good captcha will be better, but the idea to redirect can be better,
you can save in db the ip, and send then to fbi in a periodic time.
Yuri Yarlei.
www.yuriyarlei.net (under construction)
Programmer PHP, CSS, Java, PostregreSQL;
Today PHP, tomorrow Java, after the world.
Kyou wa
Maybe the $_SERVER variable has been disable in the server, if is it, you will
just need enable the $_SERVER again
Yuri Yarlei.
Programmer PHP, CSS, Java, PostregreSQL;
Today PHP, tomorrow Java, after the world.
Kyou wa PHP, ashita wa Java, sono ato sekai desu.
> From: t
Name)) {
$name = $firstName;
} else {
$name = 'Sir or Madam';
}
Yuri Yarlei.
Programmer PHP, CSS, Java, PostregreSQL;
Today PHP, tomorrow Java, after the world.
Kyou wa PHP, ashita wa Java, sono ato sekai desu.
> Date: Mon, 3 Aug 2009 10:08:08 -0700
> From: allenmcc...@
I think mysql_real_escape_string() is work well, but if you are use mysql db,
if you are using another db, the best function is addslashes but for another
special charactes you will need treat them with another ways
Yuri Yarlei.
Programmer PHP, CSS, Java, PostregreSQL;
Today PHP, tomorrow
In a project with this large number of files, is better if you let the way it
is, doing this now you can crash the project and lost much much time.
Yuri Yarlei.
Programmer PHP, CSS, Java, PostregreSQL;
Today PHP, tomorrow Java, after the world.
Kyou wa PHP, ashita wa Java, sono ato sekai desu
You can use the date_default_timezone_set(), it will set the default timezone
to your timezone choose, some server denied the access to the environment
variable
Yuri Yarlei.
Programmer PHP, CSS, Java, PostregreSQL;
Today PHP, tomorrow Java, after the world.
Kyou wa PHP, ashita wa Java, sono
, if you want more
security for some variables, encode just these
for 4
One of the intentions of the session is store informations for the easy
aplication access
for 5
I think its not a good idea, the ip can change in the middle of the aplication
Yuri Yarlei.
Programmer PHP, CSS, Java
e this error will go away
Yuri Yarlei.
Programmer PHP, CSS, Java, PostregreSQL;
Today PHP, tomorrow Java, after the world.
Kyou wa PHP, ashita wa Java, sono ato sekai desu.
> Date: Mon, 29 Jun 2009 15:10:22 +0530
> From: sures...@zensar.com
> To: php-general@lists.php.net
> Subjec
Check the mysql user permissions, then check the root directory permissions, if
you use some .htacess file, check this to.
This error occurs when you have, permissions errors, server is not working
well, .htacess errors and other things, try acess your script to with
http://127.0.0.1
Yuri
_POST['mort']) && !empty($_POST['mort']) ? "The mortgage amount
is $mort\n" : " ");
or
$msg.= ($_POST['mort'] == '' ? "The mortgage amount is $mort\n" : " ");
or
$msg.= (strlen($_POST['mort']) > 0
27;];
echo "";
}
the foreach function transform the array $rows[] (the fisrt level of
associative array) in a variable $row.
Yuri Yarlei.
Programmer PHP, CSS, Java, PostregreSQL;
Today PHP, tomorrow Java, after the world.
Kyou wa PHP, ashita wa Java, sono ato sekai desu.
> To
foo, "string");
Or maybe in your class you did not declare the variable
ex:
private $var1 = NULL;
private $var2 = NULL;
Yuri Yarlei
> From: ang...@elemental.co.za
> To: php-general@lists.php.net
> Date: Thu, 18 Jun 2009 13:20:59 +0200
> Subject: [PHP] Object of class coul
But what you trying to pass to the variable?
I already see this error, but I see when I write $$ in the variable,
you can see if you have some $$ in variables or try casting type with
the function settype();
ex:
settype($foo, "array");
settype($foo, "integer");
settype($foo, "string");
Or maybe
I agree, this list is to learn and improve skills in php laguage. not to
discriminate the others when they try to help someone or trying to learn
somethings
> Date: Tue, 16 Jun 2009 20:50:57 -0400
> From: asny...@noloh.com
> To: af.gour...@videotron.ca; php-general@lists.php.net
> Subject: RE:
tomaka wrote:
> >>>>
> >>>>
> >>>>> You can try like this,
> >>>>>
> >>>>> $row = stored data;
> >>>>>
> >>>>> and write the options like this
> >>>>
sorry, maybe I have been lazy in that comment, I admit, whem wrote that
solution I was in a such hurry and without time. I dont really read what I
wrote, but now I think this solution is good.
".$row['name']."";
}
}
?>
> Date: Wed, 17 Jun 2009 10:16:15 +0100
> From: m.f...@leedsm
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