May i change this ?
ScriptAlias /php/ "C:/WINNT/system32/inetsrv/php/"
AddType application/x-httpd-php .php .php3 .phtml
Action application/x-httpd-php "/php/php.exe"
by this other?
ScriptAlias /php/ "C:/WINNT/system32/inetsrv/php/sapi"
AddType application/x-httpd-php .php .php3 .pht
MY PROBLEMS IS. THAT I DON'T KNOW HOW TO CONFIGURE MY APACHE SERVER TO USE
MY C:\Inetpub\wwwroot\SITES I HAVE THERE
THAT'S MY PROBLEM.
THANKS FOR YOUR COLABORATION.
YOIS
- Original Message -
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, July 19, 2001 7:32 AM
Subject:
Hi agin
I have APCHE SERVER Installed in my Machine.
And i have Win2k pro installed.
And as you see i want to use.
So i having troubles to configure the WEB server.
If somebody knows how to do it, please it would help me much.
Thanks
Yassel (Cybername=YOIS)
Hi agin
I have APCHE SERVER Installed in my Machine.
And i have Win2k pro installed.
And as you sww i want to use.
So i having troubles to configure the WEB server.
If somebody knows how to do it, please it would help me much.
Thanks
Yassel (Cybername=YOIS)
Put the same text
inside php
example
" the next code
- Original Message -
From: "Petr Jůza" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, July 17, 2001 2:47 PM
Subject: [PHP] displaying icons
> Hi everybody!
> Please, have somebody any experience with displaying icons (
Hi friends
thanks averybodoy for help me
i used the solition of "Jason Bell" [EMAIL PROTECTED]
thanks Jason
with this
> try this:
>
> mysql_connect("YOUR_DB_HOST","DB_USERNAME","DB_PASSWORD");
> mysql_select_db("DB");
> $query = "select * from info where FirstName='$FirstName' and
> LastName='
Hey guys
here is my code
4: mysql_connect() or die ("Problemas conectandose a la base de datos");
5: $query="select * from info where FirstName='$FirstName' and
6: LastName='$LastName' and email='$email'";
7: $result = mysql_db_query("users", $query);
*8: $r=mysql_fetch_array($result); *
Hi again
Here is the part of before code
8:$result = mysql_db_query("users", $query);
9:$r=mysql_fetch_array($result);
10: $count=$r["count"];
And the error message is
Warning: Supplied argument is not a valid MySQL result resource in
c:\inetpub\wwwroot\PhpAndMysqlTest\test2\reg1.php3 on lin
Hi
I'm having
trouble with this part of code
9: $result = mysql_db_query("users", $query);
10: $r=mysql_fetch_array($result);
The error message is :
Warning: Supplied argument is not a valid MySQL result resource in
c:\inetpub\wwwroot\PhpAndMysqlTest\test2\reg1.php3 on line 9.
Please if some
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