hi nicole,
do you have an example what your query contains ?
maybe urlencode($pageURL) or quoting will help
greetings martin
> -Ursprüngliche Nachricht-
> Von: Nicole Lallande [mailto:[EMAIL PROTECTED]]
> Gesendet: Dienstag, 26. November 2002 15:40
> An: [EMAIL PROTECTED]
> Betreff: [PHP
hi ines,
surely ther are several possibilities to solve this problem.
i would do it like this:
put your values in three arrays
suggesting your icons represents links, put a variable after each link.
with the 'switch; case' command you can evaluate the get variables, and
generate the pages with th
same error message.
does anybody have an idea ?
thanks in advance
martin
Martin Lucas
- ICT Manager -
TechConsult GmbH
European IT-Marketing Research
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34125 Kassel
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hi chad,
on http://www.cnovak.com/ you'll find a php-class that generates native
excel-files, even with cell formatings and other more or less useful things.
greetings
martin
> -Ursprüngliche Nachricht-
> Von: Chad Day [mailto:[EMAIL PROTECTED]]
> Gesendet: Dienstag, 18. Juni 2002 16:
hi leon,
>
> Hello,
>
> Assume I have the following array:
>
> $array = array (
> "apple" => "cherry",
> "foo" => "bar",
> "wom" => "bat"
> );
>
> How could I easy remove the key and the value of the key
> "foo" from that
> array?
>
unset ($array[foo]);
> Also, what is the best
hi john,
maybe this is the right way
$where="id like ".$id;
$query="select * from ccl where '".$where."' order by AU desc";
$result=mysql_query($query);
regards
martin
> -Ursprüngliche Nachricht-
> Von: jtjohnston [mailto:[EMAIL PROTECTED]]
> Gesendet: Montag, 18. Februar 2002 08:00
>
that seems to be easy:
put every string and varchar in single quotes eg '$surname'
and every number like $fax_number without quotes
regards martin
-Ursprüngliche Nachricht-
Von: Payzillee [mailto:[EMAIL PROTECTED]]
Gesendet: Donnerstag, 29. November 2001 13:16
An: [EMAIL PROTECTED]
Betre
take a look at your table definiton.
maybe some of your fields have a diferent definition as the value you want
to insert. e.g.
fax_number in your query-string is defined as string and in your table as
integer or something like this
regards
martin
-Ursprüngliche Nachricht-
Von: Payzillee
hi adrian,
many thanks for your tip. it works fine.
kind regards
martin
-Ursprüngliche Nachricht-
Von: Adrian Ciutureanu [mailto:[EMAIL PROTECTED]]
Gesendet: Donnerstag, 12. Juli 2001 15:46
An: Martin Lucas
Cc: [EMAIL PROTECTED]
Betreff: RE: [PHP] associative arrays
$result
Hi everybody
i have the following database query:
$result=mysql_db_query("database","select item1,item2 from table");
while ($row=mysql_fetch_array($result)){
$a=$row[item1];
$b=$row[item2];
}
what i need is an associative array, with $a as
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