[PHP] htmlentities() and default_charset

ould expect htmlentities("\x82\x86\x99\x9f", ENT_QUOTES) would use the default_charset, but not htmlentities("\x82\x86\x99\x9f", ENT_QUOTES, ''). However, test scripts ext/standard/tests/strings/htmlentities10.phpt, htmlentities11.phpt, and htmlentities13.phpt all expect the d

[PHP] general question

hello i need to make a standalone application from a web php site. how can i use php-gtk ? how can i package this application ? thanks

[PHP] Object member variable names

Hi, I've got a little problem with variable naming of object members. Here is my situation: I've got a website form, whoms contents will be saved in a MySQL table with two fields: name and value. The name could be anything like "bla->test", "array[3]->test[4]->name"... Now I have a php script re

[PHP] getting the value of a javascript variable

?? has enybody a solution for this? thanx so far - hermann... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP] how to give vars to a php(shell env) script?

Martin Towell wrote: > try setting an environment variable before calling your script > > > -Original Message----- > From: Hermann Bier [mailto:[EMAIL PROTECTED]] > Sent: Wednesday, April 24, 2002 12:34 PM > To: [EMAIL PROTECTED] > Subject: [PHP] how to give

[PHP] how to give vars to a php(shell env) script?

Hi NG! how could i give some vars to a php script, that is directly executed by php-parser. for instance: #!/usr/bin/php -q is it possible at all? thanx for advance. Hermann Bier -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

[PHP] popen(); problem, the function don`t finds the command......

Hi!! i`ve wrote a little script to run under shell, so this script: #!/usr/bin/php $saslpasswd = "/usr/sbin/saslpasswd -p $username"; $saslproc = popen($saslpasswd,"w"); fputs($saslproc, $passwd); pclose($saslproc); php-parser gives me the following as output: # sh: /saslpasswd: No such file or

[PHP] popen(); problem, the function don`t finds the command...

Hi!! i`ve wrote a little script to run under shell, so this script: #!/usr/bin/php $saslpasswd = "/usr/sbin/saslpasswd -p $username"; $saslproc = popen($saslpasswd,"w"); fputs($saslproc, $passwd); pclose($saslproc); php-parser gives me the following as output: # sh: /saslpasswd: No such file or