When I use this query in PHP it works, and I get all things with the YEAR of
1977, as I expected.
$query= "SELECT * FROM my_table WHERE Year LIKE 1977 ";
But, when I use this query it does not work.
$query= "SELECT * FROM my_table WHERE Year LIKE 197* ";
I thought I should get the result of ALL
I have this simple form file:
Name:
Age:
Which passes (I wish!) data to this script:
It does not work unless I turn register_globals ON in the php.ini file. The
php
documentation leads me to believe this script SHOULD work with
register_globals
OFF.
This a NEW instasllation of the
I created a new user, and assigned privileges. Then tried to connect to the
server
and was denied access, because of a conflict between the mysql CLIENT
version
and the mysql server code due to the password encryption scheme installed in
version
4.1 of mysql. Running the following line fixed the pr
I am trying my FIRST php file with an attempt to connect
to my mySql server.
The problem is it won't connect to the database. The server IS running. The
host, username,
and password are the exact same thing I use to connect the mySqlAdmin tool
to the database.
Doesn't seem like this should be th
I am attempting to install both phpMyAdmin and phpLens. When attempting to
connect to the mySql server I get the following error message:
"Unable to connect. Please click on Previous and correct.
[Client does not support authentication protocol requested by server;
consider upgrading MySQL client
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