On Jun 24, 2011, at 2:20 PM, Jim Giner wrote:
Call me backwards, but I prefer to keep my statements simple. I
would first
obtain the POST value before trying to pull up an array element.
$stype=$_POST[''store_type'];
if (!isset($stype))
(handle missing radio button)
else
$st_name=$cho
On Jun 24, 2011, at 1:44 PM, Chris Stinemetz wrote:
radio select validation
What I am doing wrong?
I want to make sure a radio button is selected, but my current code
allows insertion even when radio button isn't selected.
At the risk of repeating myself:
From: Tamara Temple
D
Hi,
have some difficulty with my 'select'
In my select/menu, I display all the options come from a table (table_db_email)
in my database
In this table (tb_code_prmtn11_email) I have two field :
fld_email_id
fld_name_email
It works here is a code
code>
Choo
On Jun 24, 2011, at 1:35 PM, Richard Quadling wrote:
On 24 June 2011 18:23, Tamara Temple wrote:
On Jun 24, 2011, at 10:28 AM, Richard Quadling wrote:
On 24 June 2011 15:44, Vitalii Demianets
wrote:
And furthermore, I think Carthage must be destroyed.
Let's haul out the PHP war wagons!
ht
On Saturday 25 June 2011 01:24:10 Andre Polykanine wrote:
> Maybe I'm off topic, but wouldn't you consider JavaScript form
> validation? That will make your task easier and the user will see
> his/her error much earlier, before he/she submits the form.
JavaScript validation is useful
On Friday 24 June 2011 21:44:05 Chris Stinemetz wrote:
> if (!array_key_exists($_POST['store_type'], $choices)) {
>
> echo "You must select a valid choice.";
Nothing wrong to me. Perfectly valid way of checking if there is
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