On 2014-12-04 03:41:35, Jaime Fernández del Río wrote:
> nx = np.arange(A.shape[0])[:, np.newaxis]
> ny = np.arange(A.shape[1])
> C = A[nx, ny, B]
That's the correct answer--in my answer I essentially wrote
C = A[B] (== A[B, :, :])
which broadcasts the shape of B against the second and third di
On Wed, Dec 3, 2014 at 4:02 PM, Stefan van der Walt
wrote:
> Hi Catherine
>
> On 2014-12-04 01:12:30, Moroney, Catherine M (398E) <
> catherine.m.moro...@jpl.nasa.gov> wrote:
> > I have an array "A" of shape (NX, NY, NZ), and then I have a second
> array "B" of shape (NX, NY)
> > that ranges from
Posting in the correct thread now...
A slightly different way to look at it (I don't think it is exactly the
same problem, but the description reminded me of it):
http://mail.scipy.org/pipermail/numpy-discussion/2013-April/066269.html
(and I think there are some things that can be done to make tha
Hi Catherine
On 2014-12-04 01:12:30, Moroney, Catherine M (398E)
wrote:
> I have an array "A" of shape (NX, NY, NZ), and then I have a second array "B"
> of shape (NX, NY)
> that ranges from 0 to NZ in value.
>
> I want to create a third array "C" of shape (NX, NY) that holds the
> "B"-th slice
Hello,
I'm sure there's a simple solution, but I'm not seeing it so any hints would be
greatly appreciated.
I have an array "A" of shape (NX, NY, NZ), and then I have a second array "B"
of shape (NX, NY)
that ranges from 0 to NZ in value.
I want to create a third array "C" of shape (NX, NY) tha
