How about:
numpy.fromfile(filename, dtype='>i2')
Nadav
-Original Message-
From: [EMAIL PROTECTED] on behalf of Pierre GM
Sent: Fri 06-Apr-07 18:41
To: Discussion of Numerical Python
Cc:
Subject: Re: [Numpy-discussion] problem reading binary data
> In fact numpy.fromfile was the first function I tried to use but I
> couldn't manage to get it working with the byteorder I needed
> (big-endian).
a = fromfile(...)
a.byteswap(True)
--
Christopher Barker, Ph.D.
Oceanographer
Emergency Response Division
NOAA/NOS/OR&R(206) 526-6959
Thanks to everyone, really.
I already know this ml is going to be as useful as numpy itself!
In fact numpy.fromfile was the first function I tried to use but I
couldn't manage to get it working with the byteorder I needed
(big-endian).
The ['f0'] trick works very nicely though, so I think I'll us
Pierre GM wrote:
> With numpy.core.records, you create a record array. Just get the field ('f0'
> by default) to get a ndarray.
there is. Don't use numpy.core.records. Use numpy.fromfile:
import numpy
a = numpy.fromfile(filename, dtype=numpy.int16)
(filename can be a filename, or an open file
Giorgio F. Gilestro wrote:
>Hello everyone.
>
>Here I go with my first problem for this ml!
>
>I am reading a long sequence of binary data from a file using a call
>similar to the following
>
>numpy.core.records.fromfile (filename, formats='i2', byteorder='big')
>
>My problem is that this function
On Friday 06 April 2007 12:14:20 Giorgio F. Gilestro wrote:
> Is there any way I could get a 1D array (no tuples please!) directly
> from the file?
> (BTW numpy.core.records.fromstring gives the same output)
numpy.core.records.fromfile (filename, formats='i2', byteorder='big')['f0']
With numpy.c
Hello everyone.
Here I go with my first problem for this ml!
I am reading a long sequence of binary data from a file using a call
similar to the following
numpy.core.records.fromfile (filename, formats='i2', byteorder='big')
My problem is that this function returns an array of tuples rather
tha
