Olivier Delalleau writes:
> 2011/7/12 Johann Hibschman
>
> Is there any way to wrap a sequence (in particular a python list) as a
> numpy object scalar, without it being promoted to an object array?
> I found a workaround but it's a bit ugly:
> def some_call(x):
> rval = numpy.array(N
I found a workaround but it's a bit ugly:
def some_call(x):
rval = numpy.array(None, dtype='object')
rval.fill(x)
return rval
-=- Olivier
2011/7/12 Johann Hibschman
> Is there any way to wrap a sequence (in particular a python list) as a
> numpy object scalar, without it being promoted to
Is there any way to wrap a sequence (in particular a python list) as a
numpy object scalar, without it being promoted to an object array?
In particular,
np.object_([1, 2]).shape == (2,)
np.array([1,2], dtype='O').shape == (2,)
while I want
some_call([1,2]).shape = ()
Thanks,
Johann
