Hi,
actually, I meant to reply to Mark's mail, as I used his solution ;)
Thanks!
On 06/08/2010 09:21 PM, Gökhan Sever wrote:
> If we were at so or ask.scipy I would vote for Mark's solution :)
>
> Usually in cases like yours, I tend to use the shortest version of the
> solutions.
>
> On Tue, J
On Tue, Jun 8, 2010 at 2:32 PM, Hans Meine
wrote:
>
>
> Funny, that's exactly what I wanted to do (idx being a label/region image
> here),
> and what I tried today.
>
> You will be happy to hear that the even simpler solution is to just use
> fancy indexing (the name is justified here):
>
> times[
Hi!
Am 08.06.2010 um 18:24 schrieb Andreas Hilboll:
> I have an array idx, which holds int values and has a 2d shape. All
> values inside idx are 0 <= idx < n. And I have a second array times,
> which is 1d, with times.shape = (n,).
>
> Out of these two arrays I now want to create a 2d array ha
If we were at so or ask.scipy I would vote for Mark's solution :)
Usually in cases like yours, I tend to use the shortest version of the
solutions.
On Tue, Jun 8, 2010 at 2:08 PM, Andreas Hilboll wrote:
> Hi,
>
> > newtimes = [times[idx[x][y]] for x in range(2) for y in range(2)]
> > np.array(n
Hi,
> newtimes = [times[idx[x][y]] for x in range(2) for y in range(2)]
> np.array(newtimes).reshape(2,2)
> array([[104, 102],
>[103, 101]])
Great, thanks a lot!
Cheers,
Andreas.
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Not pretty, but it works:
>>> idx
array([[4, 2],
[3, 1]])
>>> times
array([100, 101, 102, 103, 104])
>>> numpy.reshape(times[idx.flatten()],idx.shape)
array([[104, 102],
[103, 101]])
>>>
On Tue, Jun 8, 2010 at 10:09 AM, Gökhan Sever wrote:
>
>
> On Tue, Jun 8, 2010 at 1
On Tue, Jun 8, 2010 at 11:24 AM, Andreas Hilboll wrote:
> Hi there,
>
> I have a problem, which I'm sure can somehow be solved using np.choose()
> - but I cannot figure out how :(
>
> I have an array idx, which holds int values and has a 2d shape. All
> values inside idx are 0 <= idx < n. And I h
Hi there,
I have a problem, which I'm sure can somehow be solved using np.choose()
- but I cannot figure out how :(
I have an array idx, which holds int values and has a 2d shape. All
values inside idx are 0 <= idx < n. And I have a second array times,
which is 1d, with times.shape = (n,).
Ou
