19/08/10 @ 18:03 (-0600), thus spake Charles R Harris:
> 2010/8/19 Ernest Adrogué
>
> > Hi,
> >
> > I was trying to use lexsort with an array of
> > datetime.date objects, but it doesn't seem to work.
> >
> > In [86]: date = np.array([datetime.date(2000, 9, 17),
> > datetime.date(2000, 10, 1),
>
2010/8/19 Ernest Adrogué
> Hi,
>
> I was trying to use lexsort with an array of
> datetime.date objects, but it doesn't seem to work.
>
> In [86]: date = np.array([datetime.date(2000, 9, 17),
> datetime.date(2000, 10, 1),
> datetime.date(2000, 10, 22),
> datetime.date(2000, 11, 1)])
>
> In [90
Hi,
I was trying to use lexsort with an array of
datetime.date objects, but it doesn't seem to work.
In [86]: date = np.array([datetime.date(2000, 9, 17),
datetime.date(2000, 10, 1),
datetime.date(2000, 10, 22),
datetime.date(2000, 11, 1)])
In [90]: date
Out[90]: array([2000-09-17, 2000-10-01
Anne Archibald gmail.com> writes:
>
> It appears that lexsort is broken in several ways, and its docstring
> is misleading.
>
> First of all, this code is not doing quite what you describe. The
> primary key here is the [5,6,7,8] column, followed by the middle and
> then by the first. This is a
2008/5/6 Eleanor <[EMAIL PROTECTED]>:
> >>> a = numpy.array([[1,2,6], [2,2,8], [2,1,7],[1,1,5]])
> >>> a
> array([[1, 2, 6],
>[2, 2, 8],
>[2, 1, 7],
>[1, 1, 5]])
> >>> indices = numpy.lexsort(a.T)
> >>> a.T.take(indices,axis=-1).T
> array([[1, 1, 5],
>[1, 2, 6],
>>> a = numpy.array([[1,2,6], [2,2,8], [2,1,7],[1,1,5]])
>>> a
array([[1, 2, 6],
[2, 2, 8],
[2, 1, 7],
[1, 1, 5]])
>>> indices = numpy.lexsort(a.T)
>>> a.T.take(indices,axis=-1).T
array([[1, 1, 5],
[1, 2, 6],
[2, 1, 7],
[2, 2, 8]])
The above does what I w
