On Sat, Oct 1, 2011 at 11:34 AM, Olivier Delalleau wrote:
> It'll work, it is equivalent to the suggestion I made in my previous post
> with the f_inplace wrapper function (and it has the same drawback that numpy
> will allocate temporary memory, which wouldn't be the case if f was working
> in-p
It'll work, it is equivalent to the suggestion I made in my previous post
with the f_inplace wrapper function (and it has the same drawback that numpy
will allocate temporary memory, which wouldn't be the case if f was working
in-place directly, by implementing it as "arr *= 2").
Note that you don
Thanks everybody for the different solutions proposed, I really appreciate.
What about this solution? So simple that I didn't think to it...
import numpy as np
from numpy import *
def f(arr):
return arr*2
a = array( [1,1,1] )
b = array( [2,2,2] )
c = array( [3,3,3] )
d = array( [4,4,4] )
Den 12.09.2011 08:52, skrev David Froger:
Hy everybody,
I'm wondering what is the (best) way to apply the same function to multiple
arrays.
I tried to experiment a bit with this. Here is from an ipython session:
Create some arrays:
In [1]: import numpy as np
In [2]: a = np.zeros(4)
In [3]
I agree with Robert, don't use locals(). I should have added a disclaimer
"this is very hackish and probably not a good idea", sorry ;) (interesting
read: http://stackoverflow.com/questions/1450275/modifying-locals-in-python)
>From what you said I think what you really want is f to work in-place.
On 09/13/2011 01:53 AM, David Froger wrote:
> Thank you Olivier and Robert for your replies!
>
> Some remarks about the dictionnary solution:
>
> from numpy import *
>
> def f(arr):
> return arr + 100.
>
> arrs = {}
> arrs['a'] = array( [1,1,1] )
> arrs['b'] = array( [2,2,2] )
> arrs['c'] = a
On Tue, Sep 13, 2011 at 01:53, David Froger wrote:
>
> Thank you Olivier and Robert for your replies!
>
> Some remarks about the dictionnary solution:
>
> from numpy import *
>
> def f(arr):
> return arr + 100.
>
> arrs = {}
> arrs['a'] = array( [1,1,1] )
> arrs['b'] = array( [2,2,2] )
> arrs[
Thank you Olivier and Robert for your replies!
Some remarks about the dictionnary solution:
from numpy import *
def f(arr):
return arr + 100.
arrs = {}
arrs['a'] = array( [1,1,1] )
arrs['b'] = array( [2,2,2] )
arrs['c'] = array( [3,3,3] )
arrs['d'] = array( [4,4,4] )
for key,value in arr
On Mon, Sep 12, 2011 at 01:52, David Froger wrote:
> Hy everybody,
>
> I'm wondering what is the (best) way to apply the same function to multiple
> arrays.
>
> For example, in the following code:
>
> from numpy import *
>
> def f(arr):
> return arr*2
>
> a = array( [1,1,1] )
> b = array( [2,2
If you can make f work in-place then you can just call map(f, [a, b, c, d]):
def f(arr):
arr *= 2
Otherwise, you can:
- Work with a list instead (a_b_c_d = map(f, a_b_c_d), with a_b_c_d = [a, b,
c, d], but this won't update the local definitions of a, b, c, d).
- Use locals():
for x in ('a', 'b
Hy everybody,
I'm wondering what is the (best) way to apply the same function to multiple
arrays.
For example, in the following code:
from numpy import *
def f(arr):
return arr*2
a = array( [1,1,1] )
b = array( [2,2,2] )
c = array( [3,3,3] )
d = array( [4,4,4] )
a = f(a)
b = f(b)
c = f(c
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