Thanks Everyone.
On Mon, Jul 21, 2008 at 6:25 PM, Charles R Harris <[EMAIL PROTECTED]>
wrote:
>
>
> On Mon, Jul 21, 2008 at 3:37 PM, Stéfan van der Walt <[EMAIL PROTECTED]>
> wrote:
>
>> 2008/7/21 Suchindra Sandhu <[EMAIL PROTECTED]>:
>> > Is that the recommended way of checking the type of the a
On Mon, Jul 21, 2008 at 3:37 PM, Stéfan van der Walt <[EMAIL PROTECTED]>
wrote:
> 2008/7/21 Suchindra Sandhu <[EMAIL PROTECTED]>:
> > Is that the recommended way of checking the type of the array? Ususally
> for
> > type checkin, I use the isinstance built-in in python, but I see that
> will
> > n
2008/7/21 Suchindra Sandhu <[EMAIL PROTECTED]>:
> Is that the recommended way of checking the type of the array? Ususally for
> type checkin, I use the isinstance built-in in python, but I see that will
> not work in this case. I must admit that I am a little confused by this. Why
> is type differe
Hi Stéfan,
Is that the recommended way of checking the type of the array? Ususally for
type checkin, I use the isinstance built-in in python, but I see that will
not work in this case. I must admit that I am a little confused by this. Why
is type different from dtype?
Thanks,
Suchindra
On Fri,
2008/7/18 Suchindra Sandhu <[EMAIL PROTECTED]>:
> Can someone please explain to me this oddity?
>
> In [1]: import numpy as n
>
> In [8]: a = n.array((1,2,3), 'i')
>
> In [9]: type(a[0])
> Out[9]:
There's more than one int32 type lying around. Rather, compare *dtypes*:
In [19]: a.dtype == np.in
Hi,
Can someone please explain to me this oddity?
In [1]: import numpy as n
In [8]: a = n.array((1,2,3), 'i')
In [9]: type(a[0])
Out[9]:
In [10]: type(a[0]) == n.int32
Out[10]: False
When I create an array with 'int', 'int32' etc it works fine
What is the type of 'i' and what is n.int0?
Th
