Re: [Numpy-discussion] inplace operations

BBands wrote: > If I have a NumPy array like so: > > [[1, 12], > [2, 13], > [3, 14], > [4, 15], > [5, 16], > [6, 15], > [7, 14]] > > How can I do an inplace diff, ending up with this? > > [[1, 0], > [2, 1], > [3, 1], > [4, 1], > [5, 1], > [6, -1], > [7, -1]] >>> import numpy as N

Re: [Numpy-discussion] inplace operations

BBands wrote: >If I have a NumPy array like so: > >[[1, 12], > [2, 13], > [3, 14], > [4, 15], > [5, 16], > [6, 15], > [7, 14]] > >How can I do an inplace diff, ending up with this? > >[[1, 0], > [2, 1], > [3, 1], > [4, 1], > [5, 1], > [6, -1], > [7, -1]] > > Probably can be done (but it's a bit

[Numpy-discussion] inplace operations

If I have a NumPy array like so: [[1, 12], [2, 13], [3, 14], [4, 15], [5, 16], [6, 15], [7, 14]] How can I do an inplace diff, ending up with this? [[1, 0], [2, 1], [3, 1], [4, 1], [5, 1], [6, -1], [7, -1]] Also, can I covert to natural logs in place? [[1, 2.4849], [2, 2.5649], [