On 1/23/2010 7:29 PM, Anne Archibald wrote:
> I had in mind accessing the underlying data through views
> that were flat:
>
> In [3]: x = np.random.random((1000,1000))
>
> In [4]: y = np.random.random((1000,1000))
>
> In [5]: xf = x.view()
>
> In [6]: xf.shape = (-1,)
>
> In [7]: yf = y.view()
>
>
On 1/23/2010 6:00 PM, Keith Goodman wrote:
> x = y.view()
Thanks, but I'm not looking for a view.
And I need x to own its data.
Alan
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2010/1/23 Alan G Isaac :
> On 1/23/2010 5:01 PM, Anne Archibald wrote:
>> If both arrays are "C contiguous", or more generally contiguous blocks
>> of memory with the same strided structure, you might get faster
>> copying by flattening them first, so that it can go in a single
>> memcpy().
>
> I m
On Sat, Jan 23, 2010 at 4:00 PM, Keith Goodman wrote:
> On Sat, Jan 23, 2010 at 2:31 PM, Alan G Isaac wrote:
> > On 1/23/2010 5:01 PM, Anne Archibald wrote:
> >> If both arrays are "C contiguous", or more generally contiguous blocks
> >> of memory with the same strided structure, you might get f
On Sat, Jan 23, 2010 at 2:31 PM, Alan G Isaac wrote:
> On 1/23/2010 5:01 PM, Anne Archibald wrote:
>> If both arrays are "C contiguous", or more generally contiguous blocks
>> of memory with the same strided structure, you might get faster
>> copying by flattening them first, so that it can go in
On 1/23/2010 5:01 PM, Anne Archibald wrote:
> If both arrays are "C contiguous", or more generally contiguous blocks
> of memory with the same strided structure, you might get faster
> copying by flattening them first, so that it can go in a single
> memcpy().
I may misuderstand this. Did you jus
2010/1/23 Alan G Isaac :
> Suppose x and y are conformable 2d arrays.
> I now want x to become a duplicate of y.
> I could create a new array:
> x = y.copy()
> or I could assign the values of y to x:
> x[:,:] = y
>
> As expected the latter is faster (no array creation).
> Are there better ways?
If
Suppose x and y are conformable 2d arrays.
I now want x to become a duplicate of y.
I could create a new array:
x = y.copy()
or I could assign the values of y to x:
x[:,:] = y
As expected the latter is faster (no array creation).
Are there better ways?
Thanks,
Alan Isaac
_
