2008/5/20 Thomas Hrabe <[EMAIL PROTECTED]>:
> given a 3d array
> a =
> numpy.array([[[1,2,3],[4,5,6]],[[7,8,9],[10,11,12]],[[13,14,15],[16,17,18]],[[19,20,21],[22,23,24]]])
> a.shape
> returns (4,2,3)
>
> so I assume the first digit is the 3rd dimension, second is 2nd dim and
> third is the first.
I am wandering what shape would be like in C
would it be
{4;2;3} or
{3;2;4}
?
so
shape[0] == 4
or
shape[0] == 3
-Original Message-
From: [EMAIL PROTECTED] on behalf of Charles R Harris
Sent: Tue 5/20/2008 10:56 AM
To: Discussion of Numerical Python
Subject: Re: [Numpy-discussion
On Tue, May 20, 2008 at 11:47 AM, Thomas Hrabe <[EMAIL PROTECTED]> wrote:
>
> Hi all,
>
> just a simple question regarding the alignment of dimensions:
>
>
> given a 3d array
> a =
> numpy.array([[[1,2,3],[4,5,6]],[[7,8,9],[10,11,12]],[[13,14,15],[16,17,18]],[[19,20,21],[22,23,24]]])
> a.shape
> r
Hi all,
just a simple question regarding the alignment of dimensions:
given a 3d array
a =
numpy.array([[[1,2,3],[4,5,6]],[[7,8,9],[10,11,12]],[[13,14,15],[16,17,18]],[[19,20,21],[22,23,24]]])
a.shape
returns (4,2,3)
so I assume the first digit is the 3rd dimension, second is 2nd dim and thi
