On Tue, Jun 1, 2010 at 6:56 AM, Keith Goodman wrote:
> On Tue, Jun 1, 2010 at 6:47 AM, Neal Becker wrote:
>> Not sure what to call this.
>>
>> Any suggestion on computing the vector:
>>
>> sum(u[i*M:i*M+N]) for i in range (len(u)/M)
>
> How about a cumsum and then a loop to take the differences o
On Tue, Jun 1, 2010 at 6:47 AM, Neal Becker wrote:
> Not sure what to call this.
>
> Any suggestion on computing the vector:
>
> sum(u[i*M:i*M+N]) for i in range (len(u)/M)
How about a cumsum and then a loop to take the differences of the
desired indices of the cumsum? Might be faster to convert
Not sure what to call this.
Any suggestion on computing the vector:
sum(u[i*M:i*M+N]) for i in range (len(u)/M)
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