thanks. My solution was much hackier.
-Mathew
On Thu, Jun 2, 2011 at 10:27 AM, Olivier Delalleau wrote:
> I think this does what you want:
>
> def seq_split(x):
> r = [0] + list(numpy.where(x[1:] != x[:-1] + 1)[0] + 1) + [None]
> return [x[r[i]:r[i + 1]] for i in xrange(len(r) - 1)]
>
> -=-
I think this does what you want:
def seq_split(x):
r = [0] + list(numpy.where(x[1:] != x[:-1] + 1)[0] + 1) + [None]
return [x[r[i]:r[i + 1]] for i in xrange(len(r) - 1)]
-=- Olivier
2011/6/2 Mathew Yeates
> Hi
> I have indices into an array I'd like split so they are sequential
> e.g.
> [1
Hi
I have indices into an array I'd like split so they are sequential
e.g.
[1,2,3,10,11] -> [1,2,3],[10,11]
How do I do this?
-Mathew
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