On Thu, Dec 18, 2008 at 07:58, David Cournapeau
wrote:
> What would be the need for a 0 item array ? If the point is to append
> some data without knowing in advance the size, a list is most likely
> more adapted to the task. An array which cannot be indexed does not
> sound that useful, but I ma
On Thursday 18 December 2008 08:00:09 Sebastian Haase wrote:
> So the question remains: how to create an array of "empty" (i.e. 0) size ?
In [1]: from numpy import *
In [2]: x = array( [] )
In [3]: x
Out[3]: array([], dtype=float64)
In [4]: x.size
Out[4]: 0
In [5]: x.shape
Out[5]: (0,)
In [6]
Sebastian Haase wrote:
> On Thu, Dec 18, 2008 at 11:44 AM, David Cournapeau
> wrote:
>
>> Prashant Saxena wrote:
>>
>>> ST = np.empty((), dtype=np.float32)
>>> ST = np.append(ST, 10.0)
>>>
>>> This works, is it proper way to do so?
>>>
>>> One more prob
>>>
>>> ST.size returns 2.
>>>
>>> W
On 12/18/2008 5:56 AM Prashant Saxena apparently wrote:
> ST = np.empty((), dtype=np.float32)
> ST = np.append(ST, 10.0)
If you really need to append elements,
you probably want to use a list and
then convert to an array afterwards.
But if you know your array size,
you can preallocate memory and
On Thu, Dec 18, 2008 at 11:44 AM, David Cournapeau
wrote:
> Prashant Saxena wrote:
>>
>> ST = np.empty((), dtype=np.float32)
>> ST = np.append(ST, 10.0)
>>
>> This works, is it proper way to do so?
>>
>> One more prob
>>
>> ST.size returns 2.
>>
>> Why? I have added only one element.
>
> You added
Prashant Saxena wrote:
>
> ST = np.empty((), dtype=np.float32)
> ST = np.append(ST, 10.0)
>
> This works, is it proper way to do so?
>
> One more prob
>
> ST.size returns 2.
>
> Why? I have added only one element.
You added one element to an array which as already one element. Empty
does not mean
December, 2008 4:20:49 PM
Subject: Re: [Numpy-discussion] array not appending
On Thu, Dec 18, 2008 at 04:19:20PM +0530, Prashant Saxena wrote:
>How do I solve this?
If you want appending in place you have to use a python list. If you don't
need modification in place, np.append returns
On Thu, Dec 18, 2008 at 04:19:20PM +0530, Prashant Saxena wrote:
>How do I solve this?
If you want appending in place you have to use a python list. If you don't
need modification in place, np.append returns an array with the appended
number.
Gaël
_
How do I solve this?
Thanks
Prashant
From: Gael Varoquaux
To: Discussion of Numerical Python
Sent: Thursday, 18 December, 2008 4:03:34 PM
Subject: Re: [Numpy-discussion] array not appending
On Thu, Dec 18, 2008 at 03:52:23PM +0530, Prashant Saxena wrote
On Thu, Dec 18, 2008 at 03:52:23PM +0530, Prashant Saxena wrote:
>In [43]: ST = np.empty([], dtype=np.float32)
>In [44]: np.append(ST, 10.0)
>Out[44]: array([ 3.8603e-38, 1.e+01])
>In [45]: np.append(ST, 10.0)
>Out[45]: array([ 3.8603e-38, 1.e+01]
Hi,
This is copied from ipython console.
In [42]: import numpy as np
In [43]: ST = np.empty([], dtype=np.float32)
In [44]: np..append(ST, 10.0)
Out[44]: array([ 3.8603e-38, 1.e+01])
In [45]: np.append(ST, 10.0)
Out[45]: array([ 3.8603e-38, 1.e+01])
In [46]: prin
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