gt; מאת: [EMAIL PROTECTED] בשם Brent Pedersen
> נשלח: ו 12-ספטמבר-08 04:19
> אל: Discussion of Numerical Python
> נושא: Re: [Numpy-discussion] array gymnastics
>
> On Thu, Sep 11, 2008 at 6:03 PM, Alan Jackson <[EMAIL PROTECTED]> wrote:
> > There has got to be a
or
hstack((a.T, b[:,None]))
Nadav.
-הודעה מקורית-
מאת: [EMAIL PROTECTED] בשם Brent Pedersen
נשלח: ו 12-ספטמבר-08 04:19
אל: Discussion of Numerical Python
נושא: Re: [Numpy-discussion] array gymnastics
On Thu, Sep 11, 2008 at 6:03 PM, Alan Jackson <[EMAIL PROTECTED]> wrote:
&
On Thu, Sep 11, 2008 at 6:03 PM, Alan Jackson <[EMAIL PROTECTED]> wrote:
> There has got to be a simple way to do this, but I'm just not seeing it.
>
a = array([[1,2,3,4,5,6],
> [7,8,9,10,11,12]])
b = array([21,22,23,24,25,26])
>
> What I want to end up with is :
>
> c = arra
There has got to be a simple way to do this, but I'm just not seeing it.
>>> a = array([[1,2,3,4,5,6],
[7,8,9,10,11,12]])
>>> b = array([21,22,23,24,25,26])
What I want to end up with is :
c = array([[1,7,21],
[2,8,22],
..
[6,12,26]])
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