"Keith Goodman" <[EMAIL PROTECTED]> writes:
> On 8/9/07, Gary Ruben <[EMAIL PROTECTED]> wrote:
>> FWIW,
>> The list comprehension is faster than using map()
>>
>> In [7]: %timeit map(lambda x:x[0],bounds)
>> 1 loops, best of 3: 49.6 -¦s per loop
>>
>> In [8]: %timeit [x[0] for x in bounds]
>>
On 8/9/07, Gary Ruben <[EMAIL PROTECTED]> wrote:
> FWIW,
> The list comprehension is faster than using map()
>
> In [7]: %timeit map(lambda x:x[0],bounds)
> 1 loops, best of 3: 49.6 -¦s per loop
>
> In [8]: %timeit [x[0] for x in bounds]
> 1 loops, best of 3: 20.8 -¦s per loop
zip is even
FWIW,
The list comprehension is faster than using map()
In [7]: %timeit map(lambda x:x[0],bounds)
1 loops, best of 3: 49.6 -¦s per loop
In [8]: %timeit [x[0] for x in bounds]
1 loops, best of 3: 20.8 -¦s per loop
Gary R.
Keith Goodman wrote:
> On 8/9/07, Nils Wagner <[EMAIL PROTECTED]>
Nils Wagner iam.uni-stuttgart.de> writes:
>
> Hi all,
>
> I have a list e.g.
> >>> bounds
> [(1950.0, 2100.0), (1800.0, 1850.0), (1600.0, 1630.0), (1400.0, 1420.0),
> (1200.0, 1210.0), (990, 1018.0), (10, 12), (12.0, 14.0), (14.0, 16.0),
> (16.0, 18.0), (18.0, 20)]
>
> How can I extract the fi
On 8/9/07, Nils Wagner <[EMAIL PROTECTED]> wrote:
> [(1950.0, 2100.0), (1800.0, 1850.0), (1600.0, 1630.0), (1400.0, 1420.0),
> (1200.0, 1210.0), (990, 1018.0), (10, 12), (12.0, 14.0), (14.0, 16.0),
> (16.0, 18.0), (18.0, 20)]
>
> How can I extract the first value of each pair given in parenthesis i
Hi all,
I have a list e.g.
>>> bounds
[(1950.0, 2100.0), (1800.0, 1850.0), (1600.0, 1630.0), (1400.0, 1420.0),
(1200.0, 1210.0), (990, 1018.0), (10, 12), (12.0, 14.0), (14.0, 16.0),
(16.0, 18.0), (18.0, 20)]
How can I extract the first value of each pair given in parenthesis i.e.
1950,1800,1600,1
