The short answer is that it was easier this way.
The ufunc is created on the fly and it needs to know several things
that are easy to get once the function is called.
Sent from my iPhone
On Aug 7, 2009, at 11:42 AM, T J wrote:
> I was wondering why vectorize doesn't make the ufunc available
I was wondering why vectorize doesn't make the ufunc available at the
topmost level
>>> def a(x,y): return x + y
>>> b = vectorize(a)
>>> b.reduce
Instead, the ufunc is stored at b.ufunc.
Also, b.ufunc.reduce() doesn't seem to exist until I *use* the
vectorized function at least once. Can