Dear Fabrice
Finally your suggestions worked :).Thanks a lot...
soon the code I'm working will be available as a part of Free Software
Foundation.
Regards
Yogesh
On Tue, Sep 22, 2009 at 11:23 PM, Fabrice Silva wrote:
> Le mardi 22 septembre 2009 à 23:00 +0530, yogesh karp
Le mardi 22 septembre 2009 à 23:00 +0530, yogesh karpate a écrit :
> This is the main thing . When I try to store it in array like
> R_time=array([R_t[0][i]]). It just stores the final value in that
> array when loop ends.I cant get out of this For loop.I really have
> this small problem. I really
On Tue, Sep 22, 2009 at 7:01 PM, Fabrice Silva wrote:
> Le mardi 22 septembre 2009 à 17:42 +0530, yogesh karpate a écrit :
> > I just tried your idea but the result is same. it didnt help .
> >
> > 2009/9/22 Nadav Horesh
> > A quick answer with going into the details of your code:
> >
> >
Le mardi 22 septembre 2009 à 17:42 +0530, yogesh karpate a écrit :
> I just tried your idea but the result is same. it didnt help .
>
> 2009/9/22 Nadav Horesh
> A quick answer with going into the details of your code:
>
> try
> plt.plot(R_time,R_amp,'go',hold=1)
רית-
> מאת: numpy-discussion-boun...@scipy.org בשם yogesh karpate
> נשלח: ג 22-ספטמבר-09 14:11
> אל: numpy-discussion@scipy.org
> נושא: [Numpy-discussion] The problem with arrays
>
> Please kindly go through following code snippet
> for i in range(a1):
>data_temp=(bpf[l
שא: [Numpy-discussion] The problem with arrays
Please kindly go through following code snippet
for i in range(a1):
data_temp=(bpf[left[0][i]:right[0][i]])# left is an array and right
is also an array
maxloc=data_temp.argmax() #taking indices of max. value of
data segment
Please kindly go through following code snippet
for i in range(a1):
data_temp=(bpf[left[0][i]:right[0][i]])# left is an array and right
is also an array
maxloc=data_temp.argmax() #taking indices of max. value of
data segment
maxval=data_temp[maxloc]
minloc=da
