Josef and Pauli,
Wow, you guys rock! I'm amazed you could pull that out so quickly.
I thank you, and PyQuante thanks you (hopefully this will make for faster
density functional theory grids).
Rick
On Fri, Sep 3, 2010 at 5:59 AM, wrote:
> On Fri, Sep 3, 2010 at 7:48 AM, Rick Muller wrote:
> >
On Fri, Sep 3, 2010 at 7:48 AM, Rick Muller wrote:
> Sorry for the rapid repost, but I thought of a much easier way to ask the
> question I asked a few minutes ago.
>
> I have two matrices, A and B, both of which are n x m. n is big (~10,000),
> and m is small (~10).
>
> I want to take the product
Fri, 03 Sep 2010 05:48:31 -0600, Rick Muller wrote:
[clip]
> I want to take the product AB such that I get a length-n vector, as in:
>
> >>> AB = zeros(n,'d')
> >>> for i in xrange(n):
> >>>AB[i] = dot(A[i,:],B[i,:])
>>> AB = np.sum(A*B, axis=1)
It does create an intermediate (n, d) matrix,
Sorry for the rapid repost, but I thought of a much easier way to ask the
question I asked a few minutes ago.
I have two matrices, A and B, both of which are n x m. n is big (~10,000),
and m is small (~10).
I want to take the product AB such that I get a length-n vector, as in:
>>> AB = zeros(n,
