On Sat, Apr 10, 2010 at 7:31 PM, Charles R Harris wrote:
>
>
> On Sat, Apr 10, 2010 at 6:17 PM, Gökhan Sever wrote:
>
>> Hello,
>>
>> Is there a simpler way to get "c" from "a"
>>
>> I[1]: a = np.arange(10)
>>
>> I[2]: b = a[3:]
>>
>> I[3]: b
>> O[3]: array([3, 4, 5, 6, 7, 8, 9])
>>
>> I[4]: c =
On Sat, Apr 10, 2010 at 6:17 PM, Gökhan Sever wrote:
> Hello,
>
> Is there a simpler way to get "c" from "a"
>
> I[1]: a = np.arange(10)
>
> I[2]: b = a[3:]
>
> I[3]: b
> O[3]: array([3, 4, 5, 6, 7, 8, 9])
>
> I[4]: c = np.insert(b, [7]*3, 0)
> O[5]: array([3, 4, 5, 6, 7, 8, 9, 0, 0, 0])
>
> a an
On Sat, Apr 10, 2010 at 5:17 PM, Gökhan Sever wrote:
> Hello,
>
> Is there a simpler way to get "c" from "a"
>
> I[1]: a = np.arange(10)
>
> I[2]: b = a[3:]
>
> I[3]: b
> O[3]: array([3, 4, 5, 6, 7, 8, 9])
>
> I[4]: c = np.insert(b, [7]*3, 0)
> O[5]: array([3, 4, 5, 6, 7, 8, 9, 0, 0, 0])
>
> a and
Hello,
Is there a simpler way to get "c" from "a"
I[1]: a = np.arange(10)
I[2]: b = a[3:]
I[3]: b
O[3]: array([3, 4, 5, 6, 7, 8, 9])
I[4]: c = np.insert(b, [7]*3, 0)
O[5]: array([3, 4, 5, 6, 7, 8, 9, 0, 0, 0])
a and c have to be same in length and the left shift must be balanced with
equal nu