On 5/1/07, Mark.Miller <[EMAIL PROTECTED]> wrote:
OK...so just for future reference...does a Numpy 'long' not directly
correspond to a Python 'long'?
No. A numpy long corresponds, more or less, to the C long long int.
In [2]: array([1],dtype=long)
Out[2]: array([1], dtype=int64)
Chuck
Mark.Miller wrote:
> OK...so just for future reference...does a Numpy 'long' not directly
> correspond to a Python 'long'?
There is no Numpy "long", per se. There is a numpy.long symbol exposed, but it
is just the builtin long type. However, numpy has no special support for
Python's unbounded lon
OK...so just for future reference...does a Numpy 'long' not directly
correspond to a Python 'long'?
Robert Kern wrote:
> Mark.Miller wrote:
>> Can someone explain this? I can't seem to coerce numpy into storing
>> large integer values. I'm sure that I'm just overlooking something
>> simple...
Mark.Miller wrote:
> Can someone explain this? I can't seem to coerce numpy into storing
> large integer values. I'm sure that I'm just overlooking something
> simple...
>
>
> >>> import numpy
> >>> a='1'*300
> >>> type(a)
>
> >>> b=int(a)
> >>> type(b)
>
> >>> c=numpy.empty((2,2),lon
Can someone explain this? I can't seem to coerce numpy into storing
large integer values. I'm sure that I'm just overlooking something
simple...
>>> import numpy
>>> a='1'*300
>>> type(a)
>>> b=int(a)
>>> type(b)
>>> c=numpy.empty((2,2),long)
>>> c[:]=b
Traceback (most recent call la
