On Fri, Jan 23, 2009 at 02:10, V. Armando Sole wrote:
> At 01:44 23/01/2009 -0600, Robert Kern wrote:
>>It is an inevitable consequence of several features interacting
>>together. Basically, Python expands "a[b] += 1" into this:
>>
>> c = a[b]
>> d = c.__iadd__(1)
>> a[b] = d
>>
>>Basically,
At 01:44 23/01/2009 -0600, Robert Kern wrote:
>It is an inevitable consequence of several features interacting
>together. Basically, Python expands "a[b] += 1" into this:
>
> c = a[b]
> d = c.__iadd__(1)
> a[b] = d
>
>Basically, the array c doesn't know that it was created by indexing a,
>so
> Judging from his for loop, he does want the integer array. He's doing
> something like histogramming.
Yup, thanks, just goes to show that it's not good to send emails after
a glass of wine late at night with slight jetlag.
Matthew
___
Numpy-discussion
On Fri, Jan 23, 2009 at 01:11, V. Armando Sole wrote:
> Hello,
>
> In an effort to suppress for loops, I have arrived to the following situation.
>
> Through vectorial logical operations I generate a set of indices for which
> the contents of an array have to be incremented. My problem can be redu
On Fri, Jan 23, 2009 at 01:39, Matthew Brett wrote:
> Hi,
>
>> #This does not work
>> import numpy
>> a=numpy.zeros(10)
>> b=numpy.ones(4, numpy.int)
>> a[b] += 1
>
> The problem here is that you are setting a[1] to a[1]+1.
>
> I think you want:
>
> import numpy
> a=numpy.zeros(10)
> b=numpy.ones
Hi,
> #This does not work
> import numpy
> a=numpy.zeros(10)
> b=numpy.ones(4, numpy.int)
> a[b] += 1
The problem here is that you are setting a[1] to a[1]+1.
I think you want:
import numpy
a=numpy.zeros(10)
b=numpy.ones(4, numpy.bool)
a[b] += 1
Best,
Matthew
Hello,
In an effort to suppress for loops, I have arrived to the following situation.
Through vectorial logical operations I generate a set of indices for which
the contents of an array have to be incremented. My problem can be reduced
to the following:
#This works
import numpy
a=numpy.zeros(1
