On Fri, Feb 20, 2009 at 02:22, Fabrice Silva wrote:
>> On Thu, Feb 19, 2009 at 17:03, Frank Peacock wrote:
>> > img[ngridn,ngride]=(ncolour[0],ncolour[1],ncolour[2])
>
> Le jeudi 19 février 2009 à 18:24 -0600, Robert Kern a écrit :
>> for i in range(3):
>> img[ngridn,ngride,i] = ncolour[i]
>
> On Thu, Feb 19, 2009 at 17:03, Frank Peacock wrote:
> > img[ngridn,ngride]=(ncolour[0],ncolour[1],ncolour[2])
Le jeudi 19 février 2009 à 18:24 -0600, Robert Kern a écrit :
> for i in range(3):
> img[ngridn,ngride,i] = ncolour[i]
Is it not possible to simply use
img[ngridn, ngride,
Many thanks Robert.
Frank
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On Thu, Feb 19, 2009 at 17:03, Frank Peacock wrote:
> Hello
>
>
>
> I would like to know whether I can do the following in some other way as
> this fails with setting an array with a sequence on each of the colour
> arrays:
>
>
>
> h,w=720,410
>
> img = ones((h,w,3), uint8)*255
>
> img[ngridn,ngri
Hello
I would like to know whether I can do the following in some other way as
this fails with setting an array with a sequence on each of the colour
arrays:
h,w=720,410
img = ones((h,w,3), uint8)*255
img[ngridn,ngride]=(ncolour[0],ncolour[1],ncolour[2])
pilImage = Image.fromarray(img, '
