On Tue, 22 Apr 2008, lorenzo bolla apparently wrote:
> M=fromfunction(lambda i,j:f(i,j,5),(1000,1000))
> P=fromfunction(lambda i,j:f(i,j,7),(1000,1000))
Maybe partial function application is nicer:
http://docs.python.org/whatsnew/pep-309.html>
fwiw,
Alan Isaac
__
Well done in python :)
Is there a "numpy way" to do that (only asking for the fun because this
solution is nice)?
Xavier, who do like lamba functions :)
> what about using lambda functions?
>
> M=fromfunction(lambda i,j:f(i,j,5),(1000,1000))
> P=fromfunction(lambda i,j:f(i,j,7),(1000,1000))
>
> L
what about using lambda functions?
M=fromfunction(lambda i,j:f(i,j,5),(1000,1000))
P=fromfunction(lambda i,j:f(i,j,7),(1000,1000))
L.
On Tue, Apr 22, 2008 at 8:42 PM, Gnata Xavier <[EMAIL PROTECTED]>
wrote:
> Hi,
>
> fromfunction is fine but I have like to be able to create 2Darrays using
> a f
Hi,
fromfunction is fine but I have like to be able to create 2Darrays using
a function of i,j but also of one (or more) parameters.
Something like that :
def f(i,j,a):
return (i+j)*a #replace that by another non trivial computation
M=fromfunction(f( hum well something like i,j,a),(1000,100
