Could you provide more details about this to the ticket I created
based on your email:
http://projects.scipy.org/scipy/numpy/ticket/636
Thanks,
On Thu, Dec 13, 2007 at 3:33 PM, Jonathan Taylor
<[EMAIL PROTECTED]> wrote:
> I was needing an array representation of ndindex since ndindex only
> give
Hey Jonathan,
Thanks for providing this. I created a ticket for now:
http://scipy.org/scipy/numpy/ticket/636
I will take some time to add this functionality to NumPy before the
end of the year.
Thanks,
--
Jarrod Millman
Computational Infrastructure for Research Labs
10 Giannini Hall, UC Berke
Hi Sebastian
N.fromiter only works on 1D arrays. I thought the following may work,
but it doesn't:
np.fromiter(np.ndindex(10,10,10),N.dtype((int,3)))
This kind of loop is probably best implemented in C, although I think
Jonathan's version is rather clever.
Regards
Stéfan
On Fri, Dec 14, 2007
Do you know about
N.fromiter()
?
-Sebastian Haase
On Dec 14, 2007 12:33 AM, Jonathan Taylor <[EMAIL PROTECTED]> wrote:
> I was needing an array representation of ndindex since ndindex only
> gives an iterator but array(list(ndindex)) takes too long. There is
> prob some obvious way to do this I
I was needing an array representation of ndindex since ndindex only
gives an iterator but array(list(ndindex)) takes too long. There is
prob some obvious way to do this I am missing but if not feel free to
include this code which is much faster.
In [252]: time a=np.array(list(np.ndindex(10,10,10,
