El Friday, 19 de January de 2007 23:40 Mark Janikas escribió:
> Hello all,
>
>
>
> I am trying to figure out the most efficient way to get the sum of
> the product of two vectors where id != id.
>
>
>
> E.g.:
>
>
>
> X = array([1,2,3])
>
> Y = array([1,2,3])
>
>
>
> Z = (1*2) + (1*3) + (2*1) + (2*3
Doh!!! Nice call. Thanks for the input.
MJ
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Timothy
Hochberg
Sent: Friday, January 19, 2007 2:52 PM
To: Discussion of Numerical Python
Subject: Re: [Numpy-discussion] Fast vector
On 1/19/07, Mark Janikas <[EMAIL PROTECTED]> wrote:
Hello all,
I am trying to figure out the most efficient way to get the sum of the
product of two vectors where id != id.
E.g.:
X = array([1,2,3])
Y = array([1,2,3])
Z = (1*2) + (1*3) + (2*1) + (2*3) + (3*1) + (3*2) = 22
I could
Hello all,
I am trying to figure out the most efficient way to get the sum of the
product of two vectors where id != id.
E.g.:
X = array([1,2,3])
Y = array([1,2,3])
Z = (1*2) + (1*3) + (2*1) + (2*3) + (3*1) + (3*2) = 22
I could obviously do this with loops, but I was wondering
