On Sun, May 15, 2011 at 20:49, Bruce Southey wrote:
> On Fri, May 13, 2011 at 4:38 PM, Robert Kern wrote:
>> On Fri, May 13, 2011 at 09:58, Bruce Southey wrote:
>>> Hi,
>>> How do you create a 'single' structured array using np.array()?
>>> Basically I am attempting to do something like this tha
On Fri, May 13, 2011 at 4:38 PM, Robert Kern wrote:
> On Fri, May 13, 2011 at 09:58, Bruce Southey wrote:
>> Hi,
>> How do you create a 'single' structured array using np.array()?
>> Basically I am attempting to do something like this that does not work:
>> a=np.array([1,2, 3,4, 5,6], dtype=np.dt
On Fri, May 13, 2011 at 09:58, Bruce Southey wrote:
> Hi,
> How do you create a 'single' structured array using np.array()?
> Basically I am attempting to do something like this that does not work:
> a=np.array([1,2, 3,4, 5,6], dtype=np.dtype([('foo', int)]))
>
> I realize that this is essentially
On Fri, May 13, 2011 at 5:03 PM, Bruce Southey wrote:
> On 05/13/2011 03:04 PM, josef.p...@gmail.com wrote:
>> On Fri, May 13, 2011 at 3:11 PM, Derek Homeier
>> wrote:
>>> Hi,
>>>
>>> just a comment since I first thought the solution below might not be
>>> what Bruce
>>> was looking for, but hav
On 05/13/2011 03:04 PM, josef.p...@gmail.com wrote:
> On Fri, May 13, 2011 at 3:11 PM, Derek Homeier
> wrote:
>> Hi,
>>
>> just a comment since I first thought the solution below might not be
>> what Bruce
>> was looking for, but having realised it's probably what he's been
>> asking for...
>>
>>
On 13 May 2011, at 22:04, josef.p...@gmail.com wrote:
>> Thus I am wondering why broadcasting should not be possible in this
>> case,
>
> Even a 1 column table is still a table (or a list of records), and a 1
> item row is still a row.
>
True, but even multiplying the shape (6, ) array e.g. with a
On Fri, May 13, 2011 at 3:11 PM, Derek Homeier
wrote:
> Hi,
>
> just a comment since I first thought the solution below might not be
> what Bruce
> was looking for, but having realised it's probably what he's been
> asking for...
>
> On 13 May 2011, at 17:20, josef.p...@gmail.com wrote:
>
>> On Fr
Hi,
just a comment since I first thought the solution below might not be
what Bruce
was looking for, but having realised it's probably what he's been
asking for...
On 13 May 2011, at 17:20, josef.p...@gmail.com wrote:
> On Fri, May 13, 2011 at 10:58 AM, Bruce Southey
> wrote:
>> Hi,
>> Ho
On Fri, May 13, 2011 at 10:58 AM, Bruce Southey wrote:
> Hi,
> How do you create a 'single' structured array using np.array()?
> Basically I am attempting to do something like this that does not work:
> a=np.array([1,2, 3,4, 5,6], dtype=np.dtype([('foo', int)]))
>
> I realize that this is essentia
Hi,
How do you create a 'single' structured array using np.array()?
Basically I am attempting to do something like this that does not work:
a=np.array([1,2, 3,4, 5,6], dtype=np.dtype([('foo', int)]))
I realize that this is essentially redundant as if A is an 1-d array
then a structured array with
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