On Fri, May 25, 2012 at 4:59 PM, Robert Kern wrote:
> On Fri, May 25, 2012 at 3:55 PM, Nathaniel Smith wrote:
>> On May 25, 2012 2:21 PM, "Robert Kern" wrote:
>>>
>>> On Thu, May 24, 2012 at 5:52 PM, Robert Kern wrote:
>>>
>>> > (Hmm, now that I think about it, the edge cases are when the strid
On Fri, May 25, 2012 at 3:55 PM, Nathaniel Smith wrote:
> On May 25, 2012 2:21 PM, "Robert Kern" wrote:
>>
>> On Thu, May 24, 2012 at 5:52 PM, Robert Kern wrote:
>>
>> > (Hmm, now that I think about it, the edge cases are when the strides
>> > are 0 or negative. 0-stride axes can simply be remov
On Fri, May 25, 2012 at 3:55 PM, Nathaniel Smith wrote:
> On May 25, 2012 2:21 PM, "Robert Kern" wrote:
>>
>> On Thu, May 24, 2012 at 5:52 PM, Robert Kern wrote:
>>
>> > (Hmm, now that I think about it, the edge cases are when the strides
>> > are 0 or negative. 0-stride axes can simply be remov
On May 25, 2012 2:21 PM, "Robert Kern" wrote:
>
> On Thu, May 24, 2012 at 5:52 PM, Robert Kern wrote:
>
> > (Hmm, now that I think about it, the edge cases are when the strides
> > are 0 or negative. 0-stride axes can simply be removed, and I think we
> > should be able to work back to a first it
On 05/25/2012 03:17 PM, Robert Kern wrote:
> On Thu, May 24, 2012 at 5:52 PM, Robert Kern wrote:
>
>> (Hmm, now that I think about it, the edge cases are when the strides
>> are 0 or negative. 0-stride axes can simply be removed, and I think we
>> should be able to work back to a first item and fl
On Thu, May 24, 2012 at 5:52 PM, Robert Kern wrote:
> (Hmm, now that I think about it, the edge cases are when the strides
> are 0 or negative. 0-stride axes can simply be removed, and I think we
> should be able to work back to a first item and flip the sign on the
> negative strides. The typica
On Thu, May 24, 2012 at 1:59 PM, Nathaniel Smith wrote:
> On Thu, May 24, 2012 at 6:07 PM, Larsen, Brian A wrote:
>> This is the stack overflow discussion mentioned.
>>
>> http://stackoverflow.com/questions/9164269/can-you-tell-if-an-array-is-a-view-of-another
>>
>> I basically implemented the an
On Thu, May 24, 2012 at 6:07 PM, Larsen, Brian A wrote:
> This is the stack overflow discussion mentioned.
>
> http://stackoverflow.com/questions/9164269/can-you-tell-if-an-array-is-a-view-of-another
>
> I basically implemented the answer from SO. I feel like the "is" gives you
> a good handle on
This is the stack overflow discussion mentioned.
http://stackoverflow.com/questions/9164269/can-you-tell-if-an-array-is-a-view-of-another
I basically implemented the answer from SO. I feel like the "is" gives you a
good handle on things since to be true they are actually the same location in
m
On Thu, May 24, 2012 at 4:10 PM, Nathaniel Smith wrote:
> On Thu, May 24, 2012 at 3:56 PM, Jonathan T. Niehof wrote:
>> On 05/23/2012 05:31 PM, T J wrote:
>>
>>> It seems that there are a number of ways to check if an array is a view.
>>> Do we have a preferred way in the API that is guaranteed t
On Thu, May 24, 2012 at 3:56 PM, Jonathan T. Niehof wrote:
> On 05/23/2012 05:31 PM, T J wrote:
>
>> It seems that there are a number of ways to check if an array is a view.
>> Do we have a preferred way in the API that is guaranteed to stay
>> available? Or are all of the various methods "here to
On Thu, May 24, 2012 at 10:56 AM, Jonathan T. Niehof wrote:
> On 05/23/2012 05:31 PM, T J wrote:
>
> > It seems that there are a number of ways to check if an array is a view.
> > Do we have a preferred way in the API that is guaranteed to stay
> > available? Or are all of the various methods "her
On 05/23/2012 05:31 PM, T J wrote:
> It seems that there are a number of ways to check if an array is a view.
> Do we have a preferred way in the API that is guaranteed to stay
> available? Or are all of the various methods "here to stay"?
We've settled on checking array.base, which I think was t
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