Thank you Neil Martinsen-Burrell and Scott Sinclair for your answers. :)
It's exactly what i wanted to know. I will use hstack and vstack to "resize" my
array.
Have a nice day.
--- On Wed, 6/17/09, Scott Sinclair wrote:
The resize method of ndarray is currently broken when the 'order'
keyword
> 2009/6/16 Cristi Constantin
>
> Good day.
> I have this array:
>
> a = array([[u'0', u'0', u'0', u'0', u'0', u' '],
> [u'1', u'1', u'1', u'1', u'1', u' '],
> [u'2', u'2', u'2', u'2', u'2', u' '],
> [u'3', u'3', u'3', u'3', u'3', u' '],
> [u'4', u'4', u'4', u'4', u'4',
On 2009-06-16 09:42 , Cristi Constantin wrote:
> Good day.
> I have this array:
>
> a = array([[u'0', u'0', u'0', u'0', u'0', u' '],
> [u'1', u'1', u'1', u'1', u'1', u' '],
> [u'2', u'2', u'2', u'2', u'2', u' '],
> [u'3', u'3', u'3', u'3', u'3', u' '],
> [u'4', u'4', u'4', u'4', u'4', u'']],
> dtyp
Good day.
I have this array:
a = array([[u'0', u'0', u'0', u'0', u'0', u' '],
[u'1', u'1', u'1', u'1', u'1', u' '],
[u'2', u'2', u'2', u'2', u'2', u' '],
[u'3', u'3', u'3', u'3', u'3', u' '],
[u'4', u'4', u'4', u'4', u'4', u'']],
dtype='http://docs.scipy.org/doc/
